In this article, we will discuss how to add a little bit of extra credit to the square-**trinomial expression x2** + 12x.

When this credit is added, it can change the look of your answer or help you solve the problem quicker. This credit is called a trinomial root.

Many problems have a solution that starts with an easy-to-remember form of the problem, but when changes are made to the problem or solution, **something harder must** be added to get the desired result.

This is called re-shaping the problem or giving a new solution. Problems with a square-trinomial expression have a perfect-square trinomial root. Here are some examples: 8x + 12 = x2 and *2 x2 – 4* = x2 – 4.

## Second, determine what value must be added to X2 to make it a perfect-square trinomial bruised

In the previous post, we determined that 4×2 + 12x = 24.

Now it is time to find the value that must be added to this value to make it a trinomial-trinomial-trinomial equilateral triangle bruised Premiership football diamond.

The trick is to use Fubinary Algebra, which is covered in a later article. In Fubinary Algebra, values are represented as letters instead of numbers.

So, 4×2 + 12x = *24 becomes x2*, and x = 4. The same process applies for 12x, which becomes y2 and z=12.

## Third, determine what value must be subtracted from 12x to make it a perfect-square trinomial bruised

In the case of a square trinomial, the * third term must* be subtracted from the

*first two terms*.

For example, if the first term of the square trinomial is 6, then the **second term must** be subtracted to make it a perfect-square trinomial.

Similarly, if the second term is 7, then the third term must be subtracted to make it a perfect-square trinomial. Thus, 12x + 7 = 0, which doesn’t work.

## Fourth, put everything together! bruised

Now, let’s talk about how to solve this problem. We know that **5 x 7** is 22, so our *solution must* be to add the *two variables together*.

To do this, we need to know the value of each variable. Since 7 x 7 is 21, our variable 6 has a value of 1.

## Try a few examples! battered

Let’s say we want to find the value of a variable x that is equal to 2. We can do this by adding a constant to x:

2 + 2 = 4

This doesn’t work for our Trinomial, however, because its middle value is not a constant.

The middle value of our Trinomial cannot be added to either side to make a perfect-square Trinomial. This is because there are **two nonzero digits** in one side and **three nonzero digits** in the other side, and if you took those away, there would still be a **nonzero digit left** over. That *digit would* have to be an odd number because otherwise the Trinomial would not add up to 1.

Luckily, there are ways to correct for this problem.