# Which Value Must Be Added To The Expression X2 + 12x To Make It A Perfect-square Trinomial?

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In this article, we will discuss how to add a little bit of extra credit to the square-trinomial expression x2 + 12x.

Many problems have a solution that starts with an easy-to-remember form of the problem, but when changes are made to the problem or solution, something harder must be added to get the desired result.

This is called re-shaping the problem or giving a new solution. Problems with a square-trinomial expression have a perfect-square trinomial root. Here are some examples: 8x + 12 = x2 and 2x2 – 4 = x2 – 4.

## Second, determine what value must be added to X2 to make it a perfect-square trinomial bruised

In the previous post, we determined that 4×2 + 12x = 24.

Now it is time to find the value that must be added to this value to make it a trinomial-trinomial-trinomial equilateral triangle bruised Premiership football diamond.

The trick is to use Fubinary Algebra, which is covered in a later article. In Fubinary Algebra, values are represented as letters instead of numbers.

So, 4×2 + 12x = 24 becomes x2, and x = 4. The same process applies for 12x, which becomes y2 and z=12.

## Third, determine what value must be subtracted from 12x to make it a perfect-square trinomial bruised

In the case of a square trinomial, the third term must be subtracted from the first two terms.

For example, if the first term of the square trinomial is 6, then the second term must be subtracted to make it a perfect-square trinomial.

Similarly, if the second term is 7, then the third term must be subtracted to make it a perfect-square trinomial. Thus, 12x + 7 = 0, which doesn’t work.

## Fourth, put everything together! bruised

Now, let’s talk about how to solve this problem. We know that 5 x 7 is 22, so our solution must be to add the two variables together.

To do this, we need to know the value of each variable. Since 7 x 7 is 21, our variable 6 has a value of 1.

## Try a few examples! battered

Let’s say we want to find the value of a variable x that is equal to 2. We can do this by adding a constant to x:

2 + 2 = 4

This doesn’t work for our Trinomial, however, because its middle value is not a constant.

The middle value of our Trinomial cannot be added to either side to make a perfect-square Trinomial. This is because there are two nonzero digits in one side and three nonzero digits in the other side, and if you took those away, there would still be a nonzero digit left over. That digit would have to be an odd number because otherwise the Trinomial would not add up to 1.

Luckily, there are ways to correct for this problem.

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